There are too many variables at play here, and not enough information provided, to give a definitive straight answer;
However, the one constant is that the greatest amount of torque applied/transmitted through the chain would be from a standing start on a steep incline, with the
greatest force being applied on the initial downstroke on the drive side - in which case the road bike is using the greater force because it is using a higher gear to
create a mechanical advantage (commence forward motion...).
This greater force is proportionally greater still in the length of chain between the top of the sprocket at the back and the top of the chainring at the front, it then decreases slightly until the same point of the next pedalling stroke is reached. The tension
through the derailleur is minimal
(unless you try and change gear during the pedalling stroke, but THAT is a whole different ball game!) as it is there to do
two things only, take up the
slack opposite the tight side
(top) of the chain and move the chain from side to side across the block/cassette.
If you were to imply that your comparison point is two cyclists, one on each type of bike, cycling together on eaxctly the same stretch of flat road in ideal conditions in the same relevant gear then the road bike is still exerting the greater force on the chain
(on the downside of the pedalling stroke on the drive side...) due to the mechanical effect of the higher ratio gears
(unless of course the mathematics shows that the proportional forces at work are INDEED the same!).
http://www.scribd.com/doc/62497413/Powe ... -and-Chain
You do the math's - I've been up since 3AM and have a splitting headache already thankyou - and my brown coat is in the wash... 